Evaluate cos[sin−141+sec−134]

=cos[sin−141+cos−143]cos(sin−141)cos(cos−143)−sin(sin−141)sin(cos−143)=431−412−411−432=43415−4147=16315−7

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Evaluate [^{-1}{1}{4}+^{-1}{4}{3}]

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Evaluate
$cos [sin^{- 1} \frac{1}{4} + sec^{- 1} \frac{4}{3}]$

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Evaluate

cos [sin^{- 1} \frac{1}{4} + sec^{- 1} \frac{4}{3}]

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= cos [sin^{- 1} \frac{1}{4} + cos^{- 1} \frac{3}{4}]

cos (sin^{- 1} \frac{1}{4}) cos (cos^{- 1} \frac{3}{4}) - sin (sin^{- 1} \frac{1}{4}) sin (cos^{- 1} \frac{3}{4})

= \frac{3}{4} 1 - \frac{1 ^{2}}{4} - \frac{1}{4} 1 - \frac{3 ^{2}}{4}

= \frac{3}{4} \frac{15}{4} - \frac{1}{4} \frac{7}{4} = \frac{3 15 - 7}{16}

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Question Text	Evaluate $cos [sin^{- 1} \frac{1}{4} + sec^{- 1} \frac{4}{3}]$
Answer Type	Text solution:1
Upvotes	150