Equation xn−1=0,n>1,n∈N, has roots 1,a1,a2,…,an−1. The value of r=1∑n−12−ar1 is

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Equation {x}^{{{n}}}-{1}={0},{n}{1},{n}{N}, { has roots } {1},

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Equation $x^{n} - 1 = 0, n > 1, n \in N, has roots 1, a_{1}, a_{2}, \dots, a_{n - 1} .$
The value of $r = 1 \sum n - 1 \frac{1}{2 - a _{r}}$ is

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Equation

x^{n} - 1 = 0, n > 1, n \in N, has roots 1, a_{1}, a_{2}, \dots, a_{n - 1} .

The value of

r = 1 \sum n - 1 \frac{1}{2 - a _{r}}

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Question Text

Equation

x^{n} - 1 = 0, n > 1, n \in N, has roots 1, a_{1}, a_{2}, \dots, a_{n - 1} .

The value of

r = 1 \sum n - 1 \frac{1}{2 - a _{r}}