cosA+cos3AsinA+sin3A=tanxAFind x;

cosA+cos3AsinA+sin3A=2cos(23A+A)cos(23A−A)2sin(23A+A)cos(23A−A)=cos4AcosAsin2AcosA=tan2A=R.H.S.Ans: 2

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{ A+ 3A}{ A+ 3A}= xA Find x;

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$\frac{sin A + sin 3 A}{cos A + cos 3 A} = tan x A$
Find $x$ ;

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Eleanor Discussed

\frac{sin A + sin 3 A}{cos A + cos 3 A} = tan x A

Find

x

;

7 mins ago

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7 mins ago

\frac{sin A + sin 3 A}{cos A + cos 3 A} = \frac{2 sin ( \frac{3 A + A}{2} ) cos ( \frac{3 A - A}{2} )}{2 cos ( \frac{3 A + A}{2} ) cos ( \frac{3 A - A}{2} )} = \frac{sin 2 A cos A}{cos 4 A cos A} = tan 2 A =

R.H.S.

Ans: 2

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Question Text	$\frac{sin A + sin 3 A}{cos A + cos 3 A} = tan x A$ Find $x$ ;
Answer Type	Text solution:1
Upvotes	150