1+i3−2−i2+1−i2=

1+i3−2−i2+1−i2=23(1−i)−52(2+i)+22(1+i)=(23−54+1)+i(−23−52+1)=101(17−9i)

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{3}{1+i}-{2}{2-i}+{2}{1-i}=

Question

$\frac{3}{1 + i} - \frac{2}{2 - i} + \frac{2}{1 - i} =$

\frac{1}{10} (17 - 9 i)

\frac{1}{10} (17 + 9 i)

- i

i

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William Discussed

\frac{3}{1 + i} - \frac{2}{2 - i} + \frac{2}{1 - i} =

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6 mins ago

\frac{3}{1 + i} - \frac{2}{2 - i} + \frac{2}{1 - i}

= \frac{3 ( 1 - i )}{2} - \frac{2 ( 2 + i )}{5} + \frac{2 ( 1 + i )}{2}

= (\frac{3}{2} - \frac{4}{5} + 1) + i (- \frac{3}{2} - \frac{2}{5} + 1)

= \frac{1}{10} (17 - 9 i)

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