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Different words being formed by arranging the letters of the w

Question

Different words being formed by arranging the letters of the word "INTERMEDIATE". All the words obtained are written in the form of a dictionary,
Number of permutations if the words start with E & ends with I

907200

\frac{10 !}{2 !}

3628800

None of these

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Different words being formed by arranging the letters of the word "INTERMEDIATE". All the words obtained are written in the form of a dictionary,

Number of permutations if the words start with E & ends with I

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

We fix

E

and

I

at the beginning and the end respectively.

E - - - - - - - - - - I

The remaining letters are:

NTERM D A T

Thus, total number of permutations =

\frac{10 !}{2 ! 2 !} = 907200

(we have 10 letters in between I and E...and in which 2E,2T are...there)

Hence,

(a)

is correct.

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Question Text	Different words being formed by arranging the letters of the word "INTERMEDIATE". All the words obtained are written in the form of a dictionary, Number of permutations if the words start with E & ends with I
Answer Type	Text solution:1
Upvotes	150