tan(90−A)cos(90−A)sin(90−A)=

= tan(90−A)cos(90−A)sin(90−A)=sinAcosAsinA×cosA=cosAsin2A×cosA=sin2A

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{(90-A)(90-A)}{ (90-A)}=

Question

$\frac{cos ( 90 - A ) sin ( 90 - A )}{tan ( 90 - A )}$ =

sin^{2} A

cos^{2} A

sin A

1

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\frac{cos ( 90 - A ) sin ( 90 - A )}{tan ( 90 - A )}

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= \frac{cos ( 90 - A ) s in ( 90 - A )}{t an ( 90 - A )}

= \frac{s in A \times cos A}{\frac{cos A}{s in A}} = \frac{s i n ^{2} A \times cos A}{cos A}

= s i n^{2} A

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