$cos (tan^{- 1} \frac{3}{4})$

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Text solutionVerified

cos θ = \frac{1}{sec θ} = \frac{1}{1 + tan ^{2} θ} = \frac{1}{1 + \frac{9}{16}} = \frac{4}{5}

cos (tan^{- 1} \frac{3}{4})

= cos (cos^{- 1} \frac{4}{5})

= \frac{4}{5}

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