cos−1(54)=tan−1(43)

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cos^{-1} ( {4}{5} )=tan^{-1} ( {3}{4} )

Question

$co s^{- 1} (\frac{4}{5}) = t a n^{- 1} (\frac{3}{4})$

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co s^{- 1} (\frac{4}{5}) = t a n^{- 1} (\frac{3}{4})

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Question Text

co s^{- 1} (\frac{4}{5}) = t a n^{- 1} (\frac{3}{4})