Consider f(x)=tan−1(1−sinx1+sinx),x∈(0,2π)˙A normal to y=f(x)at x=6πalso passes through the point:

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Question

Consider $f (x) = tan^{- 1} (\frac{1 + sin x}{1 - sin x}), x \in (0, \frac{π}{2}) ˙$ A normal to $y = f (x)$ at $x = \frac{π}{6}$ also passes through the point:

(0, 0)

(0, \frac{2 π}{3})

(\frac{π}{6}, 0)

(\frac{π}{4}, 0)

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Liam Discussed

Consider

f (x) = tan^{- 1} (\frac{1 + sin x}{1 - sin x}), x \in (0, \frac{π}{2}) ˙

A normal to

y = f (x)

x = \frac{π}{6}

also passes through the point:

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Question Text

Consider

f (x) = tan^{- 1} (\frac{1 + sin x}{1 - sin x}), x \in (0, \frac{π}{2}) ˙

A normal to

y = f (x)

x = \frac{π}{6}

also passes through the point: