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Consider circles {C}_{{{1}}}:{x}^{{{2}}}+{y}^{{{2}}}+{2}{x}-{2

Question

Consider circles
$C_{1} : x^{2} + y^{2} + 2 x - 2 y + p = 0$
$C_{2} : x^{2} + y^{2} - 2 x + 2 y - p = 0$
$C_{3} : x^{2} + y^{2} = p^{2}$
Statement-I: If the circle $C_{3}$ intersects $C_{1}$ orthogonally then $C_{2}$ does not represent a circle
Statement-II: If the circle $C_{3}$ intersects $C_{2}$ orthogonally then $C_{2}$ and $C_{3}$ have equal radii Then which of the following is true?

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Consider circles

C_{1} : x^{2} + y^{2} + 2 x - 2 y + p = 0

C_{2} : x^{2} + y^{2} - 2 x + 2 y - p = 0

C_{3} : x^{2} + y^{2} = p^{2}

Statement-I: If the circle

C_{3}

intersects

C_{1}

orthogonally then

C_{2}

does not represent a circle
Statement-II: If the circle

C_{3}

intersects

C_{2}

orthogonally then

C_{2}

and

C_{3}

have equal radii Then which of the following is true?

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Question Text

Consider circles

C_{1} : x^{2} + y^{2} + 2 x - 2 y + p = 0

C_{2} : x^{2} + y^{2} - 2 x + 2 y - p = 0

C_{3} : x^{2} + y^{2} = p^{2}

Statement-I: If the circle

C_{3}

intersects

C_{1}

orthogonally then

C_{2}

does not represent a circle
Statement-II: If the circle

C_{3}

intersects

C_{2}

orthogonally then

C_{2}

and

C_{3}

have equal radii Then which of the following is true?

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