Choose the correct answer : sin(3π−sin−1(−21)) is equal to

sin[(3π−sin−1(2−1))] [sin[(3π−sin−1(2−1))] ]sin(3π+sin−1(sin6π))( assin−1(2−1)=sin−121andsin6π=21)=sin(3π+6π)=sin2π=1

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Choose the correct answer : ( { }{3} - ^{-1} ( -{1}{2} )

Question

Choose the correct answer :
$sin (\frac{π}{3} - sin^{- 1} (- \frac{1}{2}))$ is equal to

π

- \frac{π}{2}

1

23

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Charlotte Discussed

Choose the correct answer :

sin (\frac{π}{3} - sin^{- 1} (- \frac{1}{2}))

is equal to

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5 mins ago

sin [(\frac{π}{3} - sin^{- 1} (\frac{- 1}{2}))]

[sin [(\frac{π}{3} - sin^{- 1} (\frac{- 1}{2}))]]

sin (\frac{π}{3} + sin^{- 1} (sin \frac{π}{6}))

(a s sin^{- 1} (\frac{- 1}{2}) = sin^{- 1} \frac{1}{2} an d sin \frac{π}{6} = \frac{1}{2})

= sin (\frac{π}{3} + \frac{π}{6})

= sin \frac{π}{2} = 1

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Question Text	Choose the correct answer : $sin (\frac{π}{3} - sin^{- 1} (- \frac{1}{2}))$ is equal to
Answer Type	Text solution:1
Upvotes	150