Class 11

Math

Algebra

Permutations and Combinations

A password consists of two letters of alphabet followed by three digits chosen from $0$ to $9$.Repeats are allowed. How many different possible passwords are allowed

- $492804$
- $650000$
- $676000$
- $1757600$

First two are alphabets

last three letters are nmbers

$26$ letters are there

$10$ digits are there

Therefore number of possible passwords

$=26×26×10×10×10=676000$