class 11

Math

Algebra

Permutations and Combinations

A man $X$has $7$friends, $4$of them are ladies and $3$are men. His wife $Y$also has $7$friends, $3$of them are ladies and 4 are men. Assume $X$and $Y$have no common friends. Then the total number of ways in which $X$and $Y$together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of $X$and $Y$are in the party, is :469 (2) 484 (3) 485 (4) 468