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A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of

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A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of the parabola $y^{2} = 16 x$ $0 \leq y \leq 6$ at the point art $F (x_{0}, y_{0})$ . The tangent to the parabola at $F (X_{0}, Y_{0})$ intersects the y-axis at $G (0, y)$ . The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum P) m= Q) = Maximum area of $△ E F G$ is (R) $y_{0} =$ (S) $y_{1} =$

Name: Video solution 1: A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of the parabola y2=16x 0≤y≤6 at the point art F(x0,y0). The tangent to the parabola at F(X0,Y0) intersects the y-axis at G(0,y). The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum P) m= Q) = Maximum area of △EFG is (R) y0= (S) y1=
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of the parabola y2=16x 0≤y≤6 at the point art F(x0,y0). The tangent to the parabola at F(X0,Y0) intersects the y-axis at G(0,y). The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum P) m= Q) = Maximum area of △EFG is (R) y0= (S) y1=

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Alexander Discussed

A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of the parabola

y^{2} = 16 x

0 \leq y \leq 6

at the point art

F (x_{0}, y_{0})

. The tangent to the parabola at

F (X_{0}, Y_{0})

intersects the y-axis at

G (0, y)

. The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum P) m= Q) = Maximum area of

△ E F G

is (R)

y_{0} =

(S)

y_{1} =

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Question Text	A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of the parabola $y^{2} = 16 x$ $0 \leq y \leq 6$ at the point art $F (x_{0}, y_{0})$ . The tangent to the parabola at $F (X_{0}, Y_{0})$ intersects the y-axis at $G (0, y)$ . The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum P) m= Q) = Maximum area of $△ E F G$ is (R) $y_{0} =$ (S) $y_{1} =$
Answer Type	Video solution: 1
Upvotes	150

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