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A circle S passes through the point (0, 1) and is orthogonal t

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A circle S passes through the point (0, 1) and is orthogonal to the circles $(x - 1)^{2} + y^{2} = 16$ and $x^{2} + y^{2} = 1$ . Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

Name: Video solution 1: A circle S passes through the point (0, 1) and is orthogonal to the circles (x−1)2+y2=16 and x2+y2=1. Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: A circle S passes through the point (0, 1) and is orthogonal to the circles (x−1)2+y2=16 and x2+y2=1. Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

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Liam Discussed

A circle S passes through the point (0, 1) and is orthogonal to the circles

(x - 1)^{2} + y^{2} = 16

and

x^{2} + y^{2} = 1

. Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

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Question Text	A circle S passes through the point (0, 1) and is orthogonal to the circles $(x - 1)^{2} + y^{2} = 16$ and $x^{2} + y^{2} = 1$ . Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)
Answer Type	Video solution: 1
Upvotes	150

A circle S passes through the point (0, 1) and is orthogonal to the circles (x−1)2+y2=16 and x2+y2=1. Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

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A circle S passes through the point (0, 1) and is orthogonal to the circles $(x - 1)^{2} + y^{2} = 16$ and $x^{2} + y^{2} = 1$ . Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)