(1+tan2θ).sin2θ=(1+cos2θsin2θ).sin2θ =(cos2θcos2θ+sin2θ).sin2θ =(cos2θ1).sin2θ =cos2θsin2θ =tan2θOption C is correct.

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(1 + tan^2 ) . sin^2 =

Question

$(1 + t a n^{2} θ) . s i n^{2} θ =$

s i n^{2} θ

co s^{2} θ

t a n^{2} θ

co t^{2} θ

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Text solutionVerified

(1 + t a n^{2} θ) . s i n^{2} θ = (1 + \frac{s i n ^{2} θ}{co s ^{2} θ}) . s i n^{2} θ

= (\frac{co s ^{2} θ + s i n ^{2} θ}{co s ^{2} θ}) . s i n^{2} θ

= (\frac{1}{co s ^{2} θ}) . s i n^{2} θ

= \frac{s i n ^{2} θ}{co s ^{2} θ}

= t a n^{2} θ

Option C is correct.

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