What is the degree of the differential equation(d3ydx3)2/3+4−3(d2ydx2)+5(dydx)=0?

[b] Degree of a differential equation is the power to which the highest derivative is raised when it is expressed as polynomial of derivatives. Given equation is (d3ydx3)2/3−3(d2ydx2)+5(dydx)+4=0 ⇒(d3ydx3)2/3=3d2ydx2−5dydx−4 Cube on both side. (d3ydx3)2=[3d2ydx2−5dydx−4]3 Hence, degree = 2