Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:x+y=tan−1y : y2yprime+y2+1=0
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A curve y=f(x) passes through (1,1) and tangent at P(x,y) cuts the x-axis and y-axis at A and B , respectively, such that BP:AP=3, then (a) equation of curve is xyprime−3y=0 (b) normal at (1,1) is x+3y=4 (c) curve passes through 2,8 (d) equation of curve is xyprime+3y=0
The solutions of (x+y+1) dy=dx are
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What are the order and degree respectively of the differential equationy=xdydx+dxdy?
If y=(x+1+x2−−−−−√)n, then (1+x2)d2ydx2+xdydx is