Using Lagranges mean value theorem, prove that bb−a<log(ab)<ab−a=a,where 0<a<b˙

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Using Lagranges mean value theorem, prove that {{{b}-{a}}}{{b}

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Using Lagranges mean value theorem, prove that $\frac{b - a}{b} < lo g (\frac{b}{a}) < \frac{b - a}{a} = a,$ where $0 < a < b ˙$

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Daniel Discussed

Using Lagranges mean value theorem, prove that

\frac{b - a}{b} < lo g (\frac{b}{a}) < \frac{b - a}{a} = a,

where

0 < a < b ˙

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Question Text

Using Lagranges mean value theorem, prove that

\frac{b - a}{b} < lo g (\frac{b}{a}) < \frac{b - a}{a} = a,

where

0 < a < b ˙