Two spheres of radii 3 and 4 cut orthogonally The radius of common circle is

125

12−−√5

12−−√

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[b] For the orthogonal section C1P and C2P are pendicular where C1and C2 are centers of sphere of radii 4 and 3 respectively Now C1P=4 andC2P=3, so tanθ=34 ∴ Radius of circle of intersection OP=C1Psinθ=4×35=125

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Question Text	Two spheres of radii 3 and 4 cut orthogonally The radius of common circle is
Answer Type	Text solution:1
Upvotes	150

Two spheres of radii 3 and 4 cut orthogonally The radius of common circle is

Text solutionVerified

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