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Two buildings are facing each other on a road of width 12 metr

Question

Two buildings are facing each other on a road of width $12$ metre. From the top of the first building, which is $10$ metre high, the angle of elevation of the top of the second is found to be $60^{o}$ . What is the height of the second building?

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Two buildings are facing each other on a road of width

12

metre. From the top of the first building, which is

10

metre high, the angle of elevation of the top of the second is found to be

60^{o}

. What is the height of the second building?

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Text solutionVerified

Let AB be small building and CD be tall building

∴ E D = B A = 10 m

Let

CE = x

△ BCE

tan 60 = \frac{CE}{BE}

\Rightarrow 3 = \frac{CE}{12}

\Rightarrow CE = 123

\Rightarrow CE = 20.78 m

Hence.

C D = CE + E D

C D = 20.78 + 10

C D = 30.78 m

Thus, height of the second building will be 30.78 m

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Question Text	Two buildings are facing each other on a road of width $12$ metre. From the top of the first building, which is $10$ metre high, the angle of elevation of the top of the second is found to be $60^{o}$ . What is the height of the second building?
Answer Type	Text solution:1
Upvotes	150