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The upper part of a tree is broken over by the wind makes an a

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The upper part of a tree is broken over by the wind makes an angle of $3 0^{\circ}$ with the ground and the distance from the root to the point where the top of the tree meets the ground is 15 m The height of the broken part is

15 sin 3 0^{\circ} m

15 cos 3 0^{\circ} m

15 tan 3 0^{\circ} m

15 sec 3 0^{\circ} m

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The upper part of a tree is broken over by the wind makes an angle of

3 0^{\circ}

with the ground and the distance from the root to the point where the top of the tree meets the ground is 15 m The height of the broken part is

7 mins ago

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Text solutionVerified

Let the length of the broken part =

l

Angle made by the broken part with the ground =

3 0^{\circ}

the distance on the ground =

15

m
The ground, the broken part and the unbroken part forms a right angled triangle.
Hence,

cos 30 = \frac{15}{l}

l = \frac{15}{cos 3 0 ^{\circ}}

l = 15 sec 3 0^{\circ}

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Question Text	The upper part of a tree is broken over by the wind makes an angle of $3 0^{\circ}$ with the ground and the distance from the root to the point where the top of the tree meets the ground is 15 m The height of the broken part is
Answer Type	Text solution:1
Upvotes	150