Class 10

Math

All topics

Some Applications of Trigonometry

The upper part of a tree is broken over by the wind makes an angle of $30_{∘}$ with the ground and the distance from the root to the point where the top of the tree meets the ground is 15 m The height of the broken part is

- $15sin30_{∘}m$
- $15cos30_{∘}m$
- $15tan30_{∘}m$
- $15sec30_{∘}m$

Angle made by the broken part with the ground = $30_{∘}$

the distance on the ground = $15$ m

The ground, the broken part and the unbroken part forms a right angled triangle.

Hence, $cos30=l15 $

$l=cos30_{∘}15 $

$l=15sec30_{∘}$ m