The taxi fare in a city is as follows: For the first kilometre, the fare is 8 and for the subsequent distance it is 5 per km. Taking the distance covered as x km and total fare as Rs.y, write a linear equation for this information and draw its graph.

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Filo · Accepted Answer

x0 12 y38 13 Taxi fare for first kilometer = Rs. 8Taxi fare for subsequent distance = Rs. 5Total distance covered =xTotal fare =ySince the fare for first kilometer = Rs.8According to problem,Fare for (x–1) kilometer = 5(x−1)So, the total fare y=5(x−1)+8⇒y=5(x−1)+8⇒y=5x–5+8⇒y=5x+3Hence, y=5x+3 is the required linear equation.Now the equation isy=5x+3    ...(1)Now, putting the value x=0 in (1)y=5×0+3y=0+3=3 So the solution is (0,3)Putting the value x=1 in (1)y=5×1+3y=5+3=8. So the solution is (1,8)Putting the value x=2 in (1)y=5×2+3y=10+3=13. So the solution is (2,13)

$x$	$0$	$1$	$2$
$y$	$3$	$8$	$13$

Question Text	The taxi fare in a city is as follows: For the first kilometre, the fare is $8$ and for the subsequent distance it is $5$ per km. Taking the distance covered as $x$ km and total fare as Rs. $y$ , write a linear equation for this information and draw its graph.
Answer Type	Text solution:1
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The taxi fare in a city is as follows: For the first kilometre, the fare is $8$ and for the subsequent distance it is $5$ per km. Taking the distance covered as $x$ km and total fare as Rs. $y$ , write a linear equation for this information and draw its graph.

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