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The solution set of (5+4cosθ)(2cosθ+1)=0in the interval [0,2π] is [EAMCET 2003]



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(5+4cosθ)(2cosθ+1)=0 cosθ=−5/4, which is not possible. ∴2cosθ+1=0 or cosθ=−1/2 Þ θ=2π3,4π3. Solution set is{2π3,4π3}∈[0,2π].
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Question Text | The solution set of (5+4cosθ)(2cosθ+1)=0in the interval [0,2π] is [EAMCET 2003] |
Answer Type | Text solution:1 |
Upvotes | 150 |