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The solution of the equation dydx=1−y21−x2−−−−−−√ is
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[a] dydx=1−y21−x2−−−−−−√∴dy1−y2−−−−−√=dx1−x2−−−−−√ ⇒∫dy1−y2−−−−−√=∫dx1−x2−−−−−√⇒sin−1y=sin−1x+c ∴sin−1y−sin−1x=c
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Question Text | The solution of the equation dydx=1−y21−x2−−−−−−√ is |
Answer Type | Text solution:1 |
Upvotes | 150 |