The solution of the $D E (e^{x} + 1) y d y = (y + 1) e^{x} d x$ is

e^{y} = C (e^{x} + 1) (y + 1)

e^{y} = e^{x} + y + 1

y = (e^{x} + 1) (y + 1)

n o n e o f t h ese

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Question Text

The solution of the

D E (e^{x} + 1) y d y = (y + 1) e^{x} d x

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