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The slope of the normal to the curve y = 2x^2+ 3 x at x = 0 i

Question

The slope of the normal to the curve $y = 2 x^{2} + 3 sin x$ at $x = 0$ is.

3

\frac{1}{3}

- 3

- \frac{1}{3}

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Charlotte Discussed

The slope of the normal to the curve

y = 2 x^{2} + 3 sin x

x = 0

is.

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

y = 2 x^{2} + 3 sin x

\frac{d y}{d x} = 4 x + 3 cos x

Thus slope of tangent at

x = 0

4 (0) + 3 cos 0 = 3

Hence slope of normal at the same point is

- \frac{1}{m} = - \frac{1}{3}

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Question Text	The slope of the normal to the curve $y = 2 x^{2} + 3 sin x$ at $x = 0$ is.
Answer Type	Text solution:1
Upvotes	150