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The side of a square is increasing at the rate of 0.2 cm/s. Fi

Question

The side of a square is increasing at the rate of $0.2 c m / s$ . Find the rate of increase of the perimeter of the square.

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The side of a square is increasing at the rate of

0.2 c m / s

. Find the rate of increase of the perimeter of the square.

15 mins ago

Discuss this question LIVE

15 mins ago

Text solutionVerified

Let the side of the square be

x,

We have,

P = 4 x

and

\frac{d x}{d t} = 0.2

Now,

P = 4 x \Rightarrow \frac{d P}{d t} = 4 \frac{d x}{d t} \Rightarrow \frac{d P}{d t} = 4 \times 0.2 = 0.8 c m / sec

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Question Text	The side of a square is increasing at the rate of $0.2 c m / s$ . Find the rate of increase of the perimeter of the square.
Answer Type	Text solution:1
Upvotes	150