The locus of the point which divides the double ordinates of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ in the ratio $1:2$ internally is $\frac{x^2}{a^2}+\frac{9y^2}{b^2}=1$ (b) $\frac{x^2}{a^2}+\frac{9y^2}{b^2}=\frac{1}{9}$$\frac{9x^2}{a^2}+\frac{9y^2}{b^2}=1$ (d) none of these

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