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The line, x−23=y+12=z−1−1 intersects the curve xy=c2,z=0 if c is equal to
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[c] We have, z = 0 for the point where the line intersects the curve. Therefore, x−23=y+12=0−1−1 ⇒x−23=1 and y+12=1 ⇒x=5 and y=1 Put these value in xy=c2, we get 5=c2 ⇒c=±5√
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Question Text | The line, x−23=y+12=z−1−1 intersects the curve xy=c2,z=0 if c is equal to |
Answer Type | Text solution:1 |
Upvotes | 150 |