The line which passes through the origin and intersect the two lines x−12=y+34=z−53,x−42=y+33=z−144, is

[a] Let the line be xa=yb=zc            (i) If line (i) intersects with the line x−12 =y+34=z−53, Then ∣∣∣∣a24b4−3c314∣∣∣∣=0⇒9a−7b−10c=0  (ii) From (i) and (ii), we have a1=b−3=c5 ∴ The line is x1=y−3=z5