The general solution of a differential equation of the type dydx+P1x=Q1is(A) ye∫P1dy=∫(Q1e∫P1dy)dy+C (B) ye˙∫P1dx=∫(Q1e∫P1dx)dx+C(C) xe∫P1dy=∫(Q1e∫P1dy)dy+C (D) xe∫p1dx=∫Q1e∫p1dxdx+C

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The general solution of a differential equation of the type {{

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The general solution of a differential equation of the type $\frac{d x}{d y} + P_{1} x = Q_{1}$ is(A) $y e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C$ (B) $y \overset{e}{˙}^{\int P_{1} d x} = \int (Q_{1} e^{\int P_{1} d x}) d x + C$ (C) $x e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C$ (D) $x e^{\int p_{1} d x} = \int Q_{1} e^{\int p_{1} d x} d x + C$

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The general solution of a differential equation of the type

\frac{d x}{d y} + P_{1} x = Q_{1}

is(A)

y e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C

(B)

y \overset{e}{˙}^{\int P_{1} d x} = \int (Q_{1} e^{\int P_{1} d x}) d x + C

(C)

x e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C

(D)

x e^{\int p_{1} d x} = \int Q_{1} e^{\int p_{1} d x} d x + C

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Question Text

The general solution of a differential equation of the type

\frac{d x}{d y} + P_{1} x = Q_{1}

is(A)

y e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C

(B)

y \overset{e}{˙}^{\int P_{1} d x} = \int (Q_{1} e^{\int P_{1} d x}) d x + C

(C)

x e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C

(D)

x e^{\int p_{1} d x} = \int Q_{1} e^{\int p_{1} d x} d x + C