The differential equations , find the particular solution satisfying the given condition:2xy+y2−2x2dxdy=0;y=2when x = 1
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The solution of dydx=1−x2−y2+x2y2−−−−−−−−−−−−−−−√ is
Find the orthogonal trajectories of family of curves x2+y2=cx
Find the equation of the curve in which the subnormal varies as the square of the ordinate.
The normal to a curve at P(x,y)
meet the x-axis at G˙
If the distance of G
from the origin is twice the abscissa of P
, then the curve is a
(a) parabola (b) circle
(c) hyperbola (d) ellipse
A normal at P(x,y) on a curve meets the x-axis at Q and N is the foot of the ordinate at P˙ If NQ=1+x2x(1+y2) , then the equation of curve given that it passes through the point (3,1) is
Form the differential equation of the family of parabolas with focus at the origin and the axis of symmetry along the axis.
The solution to of the differential equation(x+1)dydx−y=e3x(x+1)2 is
What is the solution of the differential equationa(xdydx+2y)=xydydx?