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The difference of the areas of two squares drawn on two line segments of different lengths is 51 sq. cm. Find the length of the greater line segment if one is longer than the other by 3 cm.
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(b): Let the length of the smaller line segment = x cm. The length of larger line segment =(x+3) cm. According to the question, (x+3)2−x2=51 ⇒x2+6x−9−x2=51 ⇒6x=51−9=42 ⇒ x=426=7 The required length =x+2=7+2=9cm.
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| Question Text | The difference of the areas of two squares drawn on two line segments of different lengths is 51 sq. cm. Find the length of the greater line segment if one is longer than the other by 3 cm. |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
