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The areas of the two similar triangles are in the ratio of the

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The areas of the two similar triangles are in the ratio of the square of the corresponding medians.

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Text solutionVerified

Solution: BD=DC=1/2BC
QS=SR=1/2QR

\frac{B D}{Q S} = \frac{D C}{S R} = \frac{B C}{Q R}

-(1)

∠ A B C

∠ P Q R

(AAA)

\frac{A B}{P Q} = \frac{B C}{Q R} = \frac{C A}{R P}

∠ B = ∠ Q

∠ A B C

∠ P Q S

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Question Text	The areas of the two similar triangles are in the ratio of the square of the corresponding medians.
Answer Type	Text solution:1
Upvotes	150