The area of a rhombus whose perimeter is 80 m and one of whose diagonal is 24 m, is

380 m2

370m2

374 m2

384m2

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The area of a rhombus whose perimeter is 80 m and one of whose diagonal is 24 m, is

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(d): Let ABCD be the rhombus of perimeter 80 m and diagonal AC=24m We have, AB+BC+CD+DA=80 ⇒4AB=80 [∴A.B=BC=CD=DA ] ⇒AB=20m In ΔABC, we have 2s=AB+BC+AC=20+20++24=64 ⇒s=32 ∴Δ1=AreaofΔABC=32×12×12×8−−−−−−−−−−−−−√=16×12=192m2 Hence, area of rhombus ABCD=2×192m2=384m2.

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