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The angles of elevation of the top of a tower from two points

Question

The angles of elevation of the top of a tower from two points A & B lying on the horizontal through the foot of the tower are respectively $3 0^{\circ}$ and $4 5^{\circ}$ of A & B are on the same side of the tower and AB = 48 m then the height of the tower is

24(

3 + 1)

25 m

26(

3 - 1)

23 m

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The angles of elevation of the top of a tower from two points A & B lying on the horizontal through the foot of the tower are respectively

3 0^{\circ}

and

4 5^{\circ}

of A & B are on the same side of the tower and AB = 48 m then the height of the tower is

6 mins ago

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6 mins ago

Text solutionVerified

Let the heightof tower be h.

t an 4 5^{\circ} = \frac{h}{BC}

l = \frac{h}{BC}

h = BC (1)

t an 3 0^{\circ} = \frac{h}{48 + BC}

\frac{1}{3} = \frac{h}{48 + BC} \Rightarrow \frac{1}{3} = \frac{h}{48 + h}

[From eq. (1)]

48+h=

3 h \Rightarrow 48 = 3 h - h

48 = h(

3 - 1) \Rightarrow h = \frac{48}{( 3 - 1 )} = 24 (3 + 1)

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Question Text	The angles of elevation of the top of a tower from two points A & B lying on the horizontal through the foot of the tower are respectively $3 0^{\circ}$ and $4 5^{\circ}$ of A & B are on the same side of the tower and AB = 48 m then the height of the tower is
Answer Type	Text solution:1
Upvotes	150