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The angle of elevation of the top of vertical tower standing o

Question

The angle of elevation of the top of vertical tower standing on a horizontal plane is observed to be $4 5^{\circ}$ from a point $A$ on the plane. Let $B$ be the point $30 m$ vertically above the point $A$ . If the angle of elevation of the top of the tower from $B$ be $3 0^{\circ}$ , then the distance (in $m$ ) of the foot of the tower from the point $A$ is

15 (3 - 3)

15 (3 + 3)

15 (1 + 3)

15 (5 - 3)

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The angle of elevation of the top of vertical tower standing on a horizontal plane is observed to be

4 5^{\circ}

from a point

A

on the plane. Let

B

be the point

30 m

vertically above the point

A

. If the angle of elevation of the top of the tower from

B

3 0^{\circ}

, then the distance (in

m

) of the foot of the tower from the point

A

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

tan 4 5^{\circ} = 1 = \frac{x + 30}{y} \Rightarrow x + 30 = y .... (i)

tan 3 0^{\circ} = \frac{1}{3} = \frac{x}{y} \Rightarrow x = \frac{y}{3} .... (ii)

from (i) and (iii)

y = 15 (3 + 3)

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Question Text	The angle of elevation of the top of vertical tower standing on a horizontal plane is observed to be $4 5^{\circ}$ from a point $A$ on the plane. Let $B$ be the point $30 m$ vertically above the point $A$ . If the angle of elevation of the top of the tower from $B$ be $3 0^{\circ}$ , then the distance (in $m$ ) of the foot of the tower from the point $A$ is
Answer Type	Text solution:1
Upvotes	150