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The angle of elevation of the top of a tower at a distance of

Question

The angle of elevation of the top of a tower at a distance of $500$ meters from the foot is $3 0^{0} .$ The height of the tower is

2503

meters

\frac{500}{3}

meters

5003

meters

250

meters

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Elijah Discussed

The angle of elevation of the top of a tower at a distance of

500

meters from the foot is

3 0^{0} .

The height of the tower is

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

From the given figure

t an 3 0^{0} = OT / OP = h /500

...(i)

t an 3 0^{0} = 1/ 3

...(ii)
From i and ii we get

h /500 = 1/ 3

h = 500/ 3

Hence answer is B

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Question Text	The angle of elevation of the top of a tower at a distance of $500$ meters from the foot is $3 0^{0} .$ The height of the tower is
Answer Type	Text solution:1
Upvotes	150