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The angle of elevation of a tower from a point 150m away from

Question

The angle of elevation of a tower from a point $150 m$ away from foot of tower is $6 0^{\circ}$ .Find the Height of tower.

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The angle of elevation of a tower from a point

150 m

away from foot of tower is

6 0^{\circ}

.Find the Height of tower.

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

The angle of elevation

6 0^{\circ}

Distance from tower

= BC = 150 m

Height of tower

= A B = h

tan 6 0^{\circ} = \frac{A B}{BC} = \frac{h e i g h t}{D i s t an ce}

tan 6 0^{\circ} = \frac{h}{150}

h = 3 \times 150

h = 1503

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Question Text	The angle of elevation of a tower from a point $150 m$ away from foot of tower is $6 0^{\circ}$ .Find the Height of tower.
Answer Type	Text solution:1
Upvotes	150