The angle of elevation at the top of a tower from a point 10 m from the foot of the tower is $3 0^{\circ}$ The height of the tower is

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The angle of elevation at the top of a tower from a point 10 m from the foot of the tower is

3 0^{\circ}

The height of the tower is

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Text solutionVerified

tan 3 0^{\circ} = \frac{h}{10} = \frac{1}{3} = \frac{h}{10}

or

h = \frac{10}{3}

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Question Text	The angle of elevation at the top of a tower from a point 10 m from the foot of the tower is $3 0^{\circ}$ The height of the tower is
Answer Type	Text solution:1
Upvotes	150