The angle of depression of a ship from the top of a tower 30 m height has measure 60. Then, the distance of the ship from the base of the tower is ........

10

30

103

303

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Text solutionVerified

∠ B A C = 90 - 6 0^{o}

= 3 0^{o}

tan 3 0^{o} = \frac{BC}{A B}

\frac{1}{3} = \frac{x}{30}

x = \frac{30}{3} \times \frac{3}{3}

x = 103

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Question Text	The angle of depression of a ship from the top of a tower 30 m height has measure 60. Then, the distance of the ship from the base of the tower is ........
Answer Type	Text solution:1
Upvotes	153

The angle of depression of a ship from the top of a tower 30 m height has measure 60. Then, the distance of the ship from the base of the tower is ........

Text solutionVerified

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