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Statement 1: For -{1}<{a}<{4},{{{.{d}{x}.}}}{{{x}^{{2}}+{2}{({

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Statement 1: For $- 1 < a < 4, \int \frac{d x}{x ^{2} + 2 ( a - 1 ) x + a + 5}$ $= λ lo g ∣ g (x) ∣ + c,$ where $λ a n d c$ are constants Statement 2: For $- 1 < a < 4, \frac{1}{x ^{2} + 2 ( a - 1 ) x + a + 5} i s c o n t \in u o u u n c t i o n$

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Statement 1: For

- 1 < a < 4, \int \frac{d x}{x ^{2} + 2 ( a - 1 ) x + a + 5}

= λ lo g ∣ g (x) ∣ + c,

where

λ a n d c

are constants Statement 2: For

- 1 < a < 4, \frac{1}{x ^{2} + 2 ( a - 1 ) x + a + 5} i s c o n t \in u o u u n c t i o n

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Question Text

Statement 1: For

- 1 < a < 4, \int \frac{d x}{x ^{2} + 2 ( a - 1 ) x + a + 5}

= λ lo g ∣ g (x) ∣ + c,

where

λ a n d c

are constants Statement 2: For

- 1 < a < 4, \frac{1}{x ^{2} + 2 ( a - 1 ) x + a + 5} i s c o n t \in u o u u n c t i o n

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