Solve the equation dxdy+(1−x2)xy=xy
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The function y=f(x) is the solution of the differential equation dxdy+x2−1xy=1−x2x4+2x in (−1,1) satisfying f(0)=0. Then ∫2323f(x)dx is
Find the orthogonal trajectories of xy=⋅
Find the order and degree of the following differential equation: edx3d3y−xdx2d2y+y=0
What is the solution of satisfying?
The solution of differential equation dxy(2x4+y)dy=(1−4xy2)x2 is given by
The normal to a curve at P(x,y)
meet the x-axis at G˙
If the distance of G
from the origin is twice the abscissa of P
, then the curve is a
(a) parabola (b) circle
(c) hyperbola (d) ellipse