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Smaller area enclosed by the circle {x}^{{2}}+{y}^{{2}}={4}and

Question

Smaller area enclosed by the circle $x^{2} + y^{2} = 4$ and the line $x + y = 2$ is
(A) $2 (π - 2)$ (B) $π - 2$ (C) $2 π - 1$ (D) $2 (π + 2)$

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Camila Discussed

Smaller area enclosed by the circle

x^{2} + y^{2} = 4

and the line

x + y = 2

is
(A)

2 (π - 2)

(B)

π - 2

(C)

2 π - 1

(D)

2 (π + 2)

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Text solutionVerified

Solution: required area=area of triangle OAB -(1/4) area of circle
=

∣ ∣ \frac{1}{2} \cdot 2 \cdot 2 - π \cdot \frac{4}{4} ∣ ∣

∣ 2 - π ∣

π - 2 u n i t^{2}

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Question Text	Smaller area enclosed by the circle $x^{2} + y^{2} = 4$ and the line $x + y = 2$ is (A) $2 (π - 2)$ (B) $π - 2$ (C) $2 π - 1$ (D) $2 (π + 2)$
Answer Type	Text solution:1
Upvotes	150