Show that the lines −45−x=4y−7=−5z+3 and 7x−8=22y−8=3z−5 are coplanar. Find the equation of the plane containing these lines.

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Show that the lines {5-x}{-4}={y-7}{4}={z+3}{-5} and {x-8}{7}=

Question

Show that the lines $\frac{5 - x}{- 4} = \frac{y - 7}{4} = \frac{z + 3}{- 5}$ and $\frac{x - 8}{7} = \frac{2 y - 8}{2} = \frac{z - 5}{3}$ are coplanar. Find the equation of the plane containing these lines.

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Chloe Discussed

Show that the lines

\frac{5 - x}{- 4} = \frac{y - 7}{4} = \frac{z + 3}{- 5}

and

\frac{x - 8}{7} = \frac{2 y - 8}{2} = \frac{z - 5}{3}

are coplanar. Find the equation of the plane containing these lines.

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Question Text

Show that the lines

\frac{5 - x}{- 4} = \frac{y - 7}{4} = \frac{z + 3}{- 5}

and

\frac{x - 8}{7} = \frac{2 y - 8}{2} = \frac{z - 5}{3}

are coplanar. Find the equation of the plane containing these lines.