Show that the function given by $f (x) = 3 x + 17$ is strictly increasing on $R$ .

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Show that the function given by

f (x) = 3 x + 17

is strictly increasing on

R

15 mins ago

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15 mins ago

Text solutionVerified

Given,

f (x) = 3 x + 17

f^{'} (x) = 3 > 0, \forall x \in R .

Thus, the given function is strictly increasing on

R

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Question Text	Show that the function given by $f (x) = 3 x + 17$ is strictly increasing on $R$ .
Answer Type	Text solution:1
Upvotes	151