Q. The value of is equal k=1∑13(sin(4π+(k−1)6π)sin(4π+k6π)1 is equal

Name: Video solution 1: Q. The value of is equal k=1∑13(sin(4π+(k−1)6π)sin(4π+k6π)1 is equal
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: Q. The value of is equal k=1∑13(sin(4π+(k−1)6π)sin(4π+k6π)1 is equal

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Q. The value of is equal $k = 1 \sum 13 (\frac{1}{sin ( \frac{π}{4} + ( k - 1 ) \frac{π}{6} ) sin ( \frac{π}{4} + k \frac{π}{6} )}$ is equal

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Q. The value of is equal

k = 1 \sum 13 (\frac{1}{sin ( \frac{π}{4} + ( k - 1 ) \frac{π}{6} ) sin ( \frac{π}{4} + k \frac{π}{6} )}

is equal

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Question Text	Q. The value of is equal $k = 1 \sum 13 (\frac{1}{sin ( \frac{π}{4} + ( k - 1 ) \frac{π}{6} ) sin ( \frac{π}{4} + k \frac{π}{6} )}$ is equal
Answer Type	Video solution: 1
Upvotes	156

Q. The value of is equal k=1∑13​(sin(4π​+(k−1)6π​)sin(4π​+k6π​)1​ is equal

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Q. The value of is equal $k = 1 \sum 13 (\frac{1}{sin ( \frac{π}{4} + ( k - 1 ) \frac{π}{6} ) sin ( \frac{π}{4} + k \frac{π}{6} )}$ is equal