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PQR is a right angles triangle Q being the right angle. Mid-points of QR and PR are respectively Q' and P? Area of ΔP′Q′R′ is
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(c): In ΔPQR and ΔP1Q1R P1Q1∥PQ ∠Q1=∠Q,∠P1=∠P ∴ΔPQR∥ΔP1Q1R ΔP1Q1=12PQ. Area of P1Q1R=12×Q1R×P1Q1 =12×12QR×12pQ =14(12×QR×PR) =14×(AreaofΔPQR)
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| Question Text | PQR is a right angles triangle Q being the right angle. Mid-points of QR and PR are respectively Q' and P? Area of ΔP′Q′R′ is |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
