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PQ is a tower standing on a horizontal plane, Q being its foot

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$PQ$ is a tower standing on a horizontal plane, $Q$ being its foot. Two points $A$ and $B$ are taken on the plane such that $A B = 32$ and $∠ Q A B$ is a right angle. It is found that $cot P A Q = 2/5$ and $cot PBQ = 3/5$ , the height of the tower is

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PQ

is a tower standing on a horizontal plane,

Q

being its foot. Two points

A

and

B

are taken on the plane such that

A B = 32

and

∠ Q A B

is a right angle. It is found that

cot P A Q = 2/5

and

cot PBQ = 3/5

, the height of the tower is

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Text solutionVerified

h = \frac{A B}{( cot ^{2} β - cot ^{2} α )} = \frac{32}{( \frac{9}{25} - \frac{4}{25} )} = 325

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Question Text	$PQ$ is a tower standing on a horizontal plane, $Q$ being its foot. Two points $A$ and $B$ are taken on the plane such that $A B = 32$ and $∠ Q A B$ is a right angle. It is found that $cot P A Q = 2/5$ and $cot PBQ = 3/5$ , the height of the tower is
Answer Type	Text solution:1
Upvotes	150